I would like to calculate
lim
Clearly this is a limit of the type \infty \cdot 0, so I'm thinking there is probably some way to turn it to \infty / \infty or 0 / 0 and then use L'Hopital but I can't think of any such trick. I cannot think of a way to do it without L'Hoptial either. Thanks for any input.
Answer
HINT: If you can prove that
\lim_{x\to 0}\frac{\sin x}{x}=1,
then you are almost done by writing x=4/n and letting n\to \infty.
No comments:
Post a Comment