Can anyone give me a hint to evaluate this integral?
∫∞0dx1+x4
I know it will involve the gamma function, but how?
Answer
HINT:
Putting x=1y,dx=−dyy2
I=∫∞0dx1+x4=∫0∞−dyy2(1+1y4)
=−∫0∞y2dy1+y4=∫∞0y2dy1+y4 as ∫baf(x)dx=−∫abf(x)dx
I=∫∞0y2dy1+y4=∫∞0x2dx1+x4
⟹2I=∫∞0dx1+x4+∫∞0x2dx1+x4=∫∞01+x21+x4dx=∫∞01x2+11x2+x2dx
Now the idea is to express the denominator as a polynomial of ∫(1x2+1)dx=x−1x=u(say)
The denominator =1x2+x2=(x−1x)2+2=u2+2
Now, complete the definite integral with u
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