Thursday, October 6, 2016

calculus - Integrals involving exponential functions and the gamma function


I'm having trouble evaluating this integral


0eax2dx


My guess is that it would evaluate into something like


012ess12dx=Γ(12)a122


When you do a substitution s=ax so that s=ax2. I'm having trouble convincing myself though that ddss=(a12) which would satisfy the answer that I provided.



Am I doing something wrong or is my guess wrong?


Answer



If you want to use the Gamma function the substitution is ax2=t, so “dx=12at1/2dt". Then the integral appears as, 12a0dtt1/2et=12aΓ(1/2) .


That's all.


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