Prove by induction:
n∑i=1(4i+1)=2n2+3n
It's just the numbers that confuse me; I know how to do a simple induction proof that first for p(k) and then for k+1 etc but I don't know how to do it with the form?
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
No comments:
Post a Comment