Saturday, March 23, 2019

summation - Prove by induction: $sumlimits_{i=1}^{n}(4i+1) = 2n^2 + 3n$


Prove by induction:
$$\sum\limits_{i=1}^{n}(4i+1) = 2n^2 + 3n$$





It's just the numbers that confuse me; I know how to do a simple induction proof that first for $p(k)$ and then for $k+1$ etc but I don't know how to do it with the form?

No comments:

Post a Comment

analysis - Injection, making bijection

I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...