Saturday, April 14, 2018

elementary number theory - Prove by induction that ab|anbn




Given a,b,nN, prove that ab|anbn. I think about induction. The assertion is obviously true for n=1. If I assume that assertive is true for a given kN, i.e.: ab|akbk, I should be able to find that ab|ak+1bk+1, but I can't do it. Any help is welcome. Thanks!


Answer



To complete the induction, note that



ak+1bk+1=ak+1akb+akbbk+1=ak(ab)+b(akbk),



then simply observe that



(ab)ak(ab),




which is obvious, and that



(ab)(akbk)



by the induction hypothesis



(ab)(akbk).



Since ab divides both summands, it divides their sum.QED




Hope this helps. Cheerio,



and as always,



Fiat Lux!!!


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