I have the following sum
5⋅4⋅3+5⋅4⋅2+5⋅4⋅1+5⋅3⋅2+5⋅3⋅1+5⋅2⋅1+4⋅3⋅2+4⋅3⋅1+4⋅2⋅1+3⋅2⋅1
It is basically 5! divided by two of the numbers in the factorial. So
5!1⋅2+5!1⋅3+5!1⋅4+...+5!3⋅5+5!4⋅5
Is there a way to write this as a single summation?
Answer
You can write it as a single sum as follows
$$\frac{5!}{1\cdot2}+\frac{5!}{1\cdot3}+\frac{5!}{1\cdot4}+...+\frac{5!}{3\cdot5}+\frac{5!}{4\cdot5}=5!\sum_{1\le i
No comments:
Post a Comment