Given a,b,n∈N, prove that a−b|an−bn. I think about induction. The assertion is obviously true for n=1. If I assume that assertive is true for a given k∈N, i.e.: a−b|ak−bk, I should be able to find that a−b|ak+1−bk+1, but I can't do it. Any help is welcome. Thanks!
Answer
To complete the induction, note that
ak+1−bk+1=ak+1−akb+akb−bk+1=ak(a−b)+b(ak−bk),
then simply observe that
(a−b)∣ak(a−b),
which is obvious, and that
(a−b)∣(ak−bk)
by the induction hypothesis
(a−b)∣(ak−bk).
Since a−b divides both summands, it divides their sum.QED
Hope this helps. Cheerio,
and as always,
Fiat Lux!!!
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