Is there a continuous bijection from open interval $(0,1)$ to $[0,1]$. The answer is not. How to prove?
I think it may proceed by contradiction and apply open mapping theorem. However, $(0,1)$ is not complete. I get stuck.
Is there a continuous bijection from open interval $(0,1)$ to $[0,1]$. The answer is not. How to prove?
I think it may proceed by contradiction and apply open mapping theorem. However, $(0,1)$ is not complete. I get stuck.
I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...
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