Tuesday, May 9, 2017

summation - Sum the first n terms of the series 1cdot3cdot22+2cdot4cdot32+3cdot5cdot42+cdots

Sum the first n terms of the series: 1322+2432+3542+.


This was asked under the heading using method of difference and the answer given was Sn=110n(n+1)(n+2)(n+3)(2n+3).




First, I get Un=n(n+2)(n+1)2.


Then I tried to make Un=VnVn1 in order to get Sn=VnV0. But I really don't know how can I figure this out.

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