Saturday, May 13, 2017

set theory - For any two sets A,B , |A|leq|B| or |B|leq|A|


Let A,B be any two sets. I really think that the statement |A||B| or |B||A| is true. Formally:



AB[|A||B| |B||A|]



If this statement is true, what is the proof ?


Answer




This claim, the principle of cardinal comparability (PCC), is equivalent to the Axiom of Choice.


If the Axiom of Choice is true then Zorn's Lemma is true and a proof of the PCC is a classical application of Zorn's Lemma.


If PCC holds then using Hartogs' Lemma it is quite easy to show that The Well-Ordering-Princple holds, which in turn implies (easily) the Axiom of Choice.


A complete presentation of these (and some other) equivalences, is treated in a rather elementary fashion but including all the details, in the book: http://www.staff.science.uu.nl/~ooste110/syllabi/setsproofs09.pdf starting on page 31.


No comments:

Post a Comment

analysis - Injection, making bijection

I have injection f:AB and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...