Can someone give me a hint on how to evaluate the closed form of the following integral? According to Wolfram Alpha, this evaluates to π8log(2).
π/4∫0log(1+tanx)dx
Thanks.
p.s - Hints are preferred over complete solutions.
Answer
Hint. By the change of variable
x=π4−u,dx=−du,1+tanx=?log(1+tanx)=?
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