Can someone give me a hint on how to evaluate the closed form of the following integral? According to Wolfram Alpha, this evaluates to $\dfrac{\pi}8\log(2)$.
$$\int\limits_0^{\pi/4}\log(1+\tan x)\,\mathrm dx$$
Thanks.
p.s - Hints are preferred over complete solutions.
Answer
Hint. By the change of variable
$$
x=\frac{\pi}4-u, \qquad dx=-du, \qquad 1+ \tan x=? \qquad \log(1+ \tan x)=?
$$
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