I did:
ca=cb∗k+r⇔ca−cb∗k=rc(a−bk)=ra−bk=r/ca=bk+r/c
So, gcd(a,b)=r/c
What do I do next?
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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