Determine if this series ∞∑n=1(n!)2(2n)!
converges or diverges, and prove your answer?
I've been able to prove similar problems, but I'm confused now that there's a factorial involved. Can someone help me out here?
Answer
Let an be the n=th term. We use the Ratio Test, and calculate limn→∞an+1an. We have
an+1an=((n+1)!)2(2n+2)!(n!)2(2n)!=((n+1)!)2(2n)!(n!)2(2n+2)!
Now we start to simplify. Note that (n+1)!n!=n+1 and (2n)!(2n+2)!=1(2n+1)(2n+2), so our ratio simplifies to
(n+1)2(2n+1)(2n+2),
which further simplifies to
n+12(2n+1).
Now find the limit as n→∞, perhaps by dividing top and bottom by n. The limit is 14<1, so we have convergence.
No comments:
Post a Comment