Calculate the limit without using de l'Hopital:
limx→0x−sinx1−cosx
I want to use the limit:limx→0sinxx=1
but I don't know how to do it.
I manipulated the expression to get limx→0xx−sinx−limx→0sinx1−cosx
but I don't know where to go from here.
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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