Can someone confirm these equations below? I got it from my college textbook, unfortunately there are no proofs and more importantly I cannot seem to find any other sources that say have these equations.
∫√a2−x2dx=x√a2−x22+a22sin−1(xa)+C
∫√x2+a2dx=x√x2+a22+a22ln(x+√x2+a2)+C
∫√x2−a2dx=x√x2−a22−a22ln(x+√x2−a2)+C
No comments:
Post a Comment