Saturday, November 28, 2015

Divisibility proof with co-prime numbers




Let a,b be co-prime. Prove that for every integer n>a it is true that a|(n+kb) for some k with 0<=k<a.



I have a feeling this is very basic stuff and I feel like there is a very simple intuitive proof and it's on the tip of my tongue but I just can't express it.


Answer



Recall that for any integers a,b (not both zero) the extended Euclidean algorithm allows you to find integers x,yZ such that ax+by=d where d is the greatest common divisor of a,b.



So in your case, there exist x,yZ such that ax+by=1 (since a,b are relatively prime). Thus ax=1by. Multiply through by n and you have your result. :)


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