Thursday, August 29, 2019

calculus - Computing limxto0+fractan(x)xx3 without L'Hôpital's rule.






Computing limx0+tan(x)xx3 without L'Hopital




Say limx0+tan(x)xx3=L




For L:
L=limx0tanxxx3L=limx0tan2x2x8x34L=limx012tan2xxx33L=limx012tan2xtanxx3=limx0tanxx11tan2x1x2=limx0(tanx)3x3=1L=13



I found that in another Q, can someone tell me why




L=limx0tanxxx3=limx0tan2x2x8x3


Answer



If x=2y then y0 when x0, so limx0f(x)=limy0f(2y).


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