I am having trouble verifying the first step where the author makes use of Cauchy-Schwarz inequality.
https://gbas2010.wordpress.com/2011/10/16/inequality-53-vo-quoc-ba-can/
I am unsure how he chooses the terms from (a+b+c) to square and multiple on the LHS.
Answer
He is using the two variable form of the inequality, that is
(x2+y2)(z2+w2)≥(xz+yw)2
Now set x=√a2+b2, y=c, z=a+b√a2+b2 and w=1 and we get
((√a2+b2)2+c2)((a+b√a2+b2)2+1)≥(√a2+b2a+b√a2+b2+c⋅1)2(a2+b2+c2)((a+b)2a2+b2+1)≥(a+b+c)2
Which is the first step of the solution.
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