I got a hard time to understand the Theorem from Cauchy Mean Value Theorem. Could someone please to help me explain this?
Let I be an open interval and n be a natural number and suppose that the function f:I→R has n derivatives. Suppose also that the point x0 in I:
f(k)(x0)=0 for 0≤k≤n−1
Then, for each point x≠x0 in I, there is a point z strictly between x and x0 at which
f(x)=f(n)(z)n!(x−x0)n
Then my homework is giving f(x)=(x−2)5 with f(x0)=f′(x0)=...=fn−1(x0) with x0=2 and n=3, find all possible z to satisfy the Theorem above.
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