real analysis - Prove: ${a_n}$ converges to $a$

Given the sequence ${b_n}$, let $lim_{n \to \infty}\ b_n = b$.

Suppose that the sequence ${a_n}$ and the number $a$ have the property for which there exists $M\in \mathbb{R}$ and there exists $N \in \mathbb{N}$ such that

$$|a_n - a| \leq M\cdot |b_n - b|, \ \forall n\in \mathbb{N}: \ n \geq N$$

Prove that the $\lim_{n \to \infty} \ a_n = a$.

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I need to show that:

$$\forall \epsilon > 0 \ \ \exists N \in \mathbb{N}: \ \forall n \geq N: |a_n - a| < \epsilon$$

I know how to set $\epsilon$ such that $\epsilon > 0$.
I’m lost from here. Because ${b_n}$ converges I know

$|b_n - b| < \epsilon$

And I think it’s safe to assume:

$|b_n - b| \leq M\cdot |b_n - b|$.

So I could prove this either by showing

$$|a_n - a| \leq |b_n - b|$$

Or,

$$M \cdot |b_n - b| < \epsilon$$

But I’m not sure how to start either way. Any suggestions?