This is what I did
Can anyone tell me what's wrong me or the question?
Answer
You did the case $y=4x$, and got answers $x=1$ and $x=-\frac{9}{4}$. Neither is a solution of the original equation. It is easy to verify that when $y=4x$ we have $\sqrt{\frac{x}{y}}-\sqrt{\frac{y}{x}}=-\frac{3}{2}$.
When you squared, you introduced extraneous roots. Only $x=4y$ leads to a solution of the system.
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