Saturday, June 24, 2017

real analysis - How to evaluate limxto0frac(sin(2x)2sin(x))4(3+cos(2x)4cos(x))3?




limx0(sin(2x)2sin(x))4(3+cos(2x)4cos(x))3



without L'Hôpital.



I've tried using equivalences with (sin(2x)2sin(x))4 and arrived at x12 but I don't know how to handle (3+cos(2x)4cos(x))3. Using cos(2x)=cos2(x)sin2(x) hasn't helped, so any hint?


Answer



Hint: Note that
3+cos(2x)4cos(x)=3+2cos2(x)14cos(x)=2(cos(x)1)2,


and that

sin(2x)2sin(x)=2sin(x)cos(x)2sin(x)=2sin(x)(cos(x)1).


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