calculus - $lim_{x to infty} frac {e^{x/2}}{2^x}$

How do i know what is the limit :

$$\lim_{x \to \infty} \frac {e^{x/2}}{2^x}$$

Because with l'hopital it is imposible to say, as the nth derivatives of both ${e^{x/2}}$and ${2^x}$ are always infinity...
I could use a hint that helps me think this through

Answer

$$\large\frac{e^{x/2}}{2^x}=\frac{e^{x/2}}{e^{x\ln(2)}}=e^{x\left[\frac12-\ln(2)\right]}\to\ ...$$