algebra precalculus - How to find the magnitude squared of square root of a complex number

I'm trying to simplify the expression

$$\left|\sqrt{a^2+ibt}\right|^2$$

where $a,b,t \in \Bbb R$.

I know that by definition

$$\left|\sqrt{a^2+ibt}\right|^2 = \sqrt{a^2+ibt}\left(\sqrt{a^2+ibt}\right)^*$$

But how do you find the complex conjugate of the square root of a complex number? And what is the square root of a complex number (with arbitrary parameters) for that matter?

Answer

For any complex number $z$, and any square root $\sqrt{z}$ of $z$ (there are two), we have
$$\bigl|\sqrt{z}\bigr|=\sqrt{|z|}$$
Therefore
$$\bigl|\sqrt{a^2+ibt}\bigr|^2=\sqrt{|a^2+ibt|^2}=|a^2+ibt| = \sqrt{a^4+b^2t^2}$$