Friday, April 7, 2017

real analysis - limprightarrowinfty||x||p=||x||infty given ||x||infty=max(|x1|,|x2|)

I have seen the proof done different ways, but none using the norm definitions provided.



Given:
||x||p=(|x1|p+|x2|p)1/p and ||x||=max(|x1|,|x2|)



Prove:
limpxp=x




I have looked at the similar questions:
The l-norm is equal to the limit of the lp-norms. and Limit of xp as p but they both seem to use quite different approaches (we have not covered homogeneity so that is out of the question, and the other uses a different definition for the infity norm).

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