I have seen the proof done different ways, but none using the norm definitions provided.
Given:
||x||p=(|x1|p+|x2|p)1/p and ||x||∞=max(|x1|,|x2|)
Prove:
limp→∞‖x‖p=‖x‖∞
I have looked at the similar questions:
The l∞-norm is equal to the limit of the lp-norms. and Limit of ‖x‖p as p→∞ but they both seem to use quite different approaches (we have not covered homogeneity so that is out of the question, and the other uses a different definition for the infity norm).
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