Find the sum of the first 75 terms of the arithmetic sequence that starts 5,8,11,…
The answer is 8700.
I found a formula to be 3x+2.
So the 1st term is
3(1)+2=5
2nd term
3(2)+2=8
3rd term
3(3)+2=11
And so on to the 75th term
3(75)+2=227
I did not get the right answer? What did I do wrong? Please help?
Answer
u1=5
u2=8=5+3
u3=11=5+2.3
u75=5+74.3=227
S=5+8+11+...+224+227
S=227+224+...8+5
by sum
2S=232+232+...232=232.75
S=116.75=8700
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