This is what I did:
√3x+√2x=17
⟹√3x+√2x=17
⟹√3√x+√2√x=17
⟹√x(√3+√2)=17
⟹x(5+2√6)=289
I don't know how to continue. And when I went to wolfram alpha, I got:
x=−289(2√6−5)
Could you show me the steps to get the final result?
Thank you.
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