Sunday, April 16, 2017

algebra precalculus - Solve sqrt3x+sqrt2x=17

This is what I did:
3x+2x=17


3x+2x=17

3x+2x=17

x(3+2)=17

x(5+26)=289

I don't know how to continue. And when I went to wolfram alpha, I got:
x=289(265)

Could you show me the steps to get the final result?

Thank you.

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