Find the sum of the series 11⋅2+1⋅31⋅2⋅3⋅4+1⋅3⋅51⋅2⋅3⋅4⋅5⋅6+.... This type of questions generally require a trick or something and i am not able to figure that out. My guess is that it has something to do with exponential series or binomial series. Any help?
Answer
Sorry guys, got it.
11⋅2+1⋅31⋅2⋅3⋅4+1⋅3⋅51⋅2⋅3⋅4⋅5⋅6+...=12⋅11!+122⋅12!+123⋅13!+...=e12−1.
The first equality holds after cancelling the common terms in the numerator and denominator
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