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cos6A+sin6A=1−3sin2Acos2A
Starting from the left hand side (LHS)
LHS=(cos2A)3+(sin2A)3=(cos2A+sin2A)(cos4A−cos2Asin2A+sin4A)=cos4A−cos2Asin2A+sin4A
Can anyone help me to continue from here
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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