trigonometry - How is it solved: $sin(x) + sin(3x) + sin(5x) +dotsb + sin(2n - 1)x =$

The problem is to find the summary of this statement:
$$\sin(x) + \sin(3x) + \sin(5x) + \dotsb + \sin(2n - 1)x = $$

I've tried to rewrite all sinuses as complex numbers but it was in vain. I suppose there is much more complicated method to do this. I think it may be solved somehow using complex numbers or progressoins.

How it's solved using complex numbers or even without them if possible?

Thanks a lot.