I need to solve this simultaneous equation: $$7x-(3\sqrt{5})y=9\sqrt{5}$$ and $$(2\sqrt5)x+y=34$$ I tried to multiple everything by $$\sqrt5$$ And then I got: $$7x\cdot(\sqrt5)-15y=45$$ and $$10x+(\sqrt5)\cdot y=34\cdot\sqrt5$$
But from here on i dont know how to make $x$ or $y$ the same, so I could $-$ or $+$ the 2 equations and solve it.
Or even the way I started it was wrong?
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