It follows easily from the convergence of ∑∞n=02nn! that
limn→∞2nn!=0
Other than the Stirling's formula, are there any "easy" alternatives to show (1)?
Answer
Yes: note that
0≤2nn!≤2(23)n−2
for n≥3, and then use the squeeze theorem.
It follows easily from the convergence of ∑∞n=02nn! that
limn→∞2nn!=0
Answer
Yes: note that
0≤2nn!≤2(23)n−2
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