A trigonometry rule says that sin2α=2sinα×cosα. Does this also apply to sin2x when x=n×α?
For example:
sin4α=2sin2α×cos2α
sin10α=2sin5α×cos5α
Answer
You can think of this as an equality of functions. It is saying that sin2(−)=2sin(−)cos(−), where the argument of the function goes where the (−) is. You get the usual identity by evaluating these functions on α (whatever α is), but you can put any expression you like in there, such as nα, 1α, eα, etc. As long as everything is properly defined (for example if you substitute in 1α then 0 is no longer a permissible value), you'll always get a true identity.
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