calculus - Is it possible to solve this limit without Hopital / Taylor / derivatives: $limlimits_{x to 0} frac{x-sin(x)}{x^3} = frac{1}{6}$?

It's simple to prove with Hopital that

$$\lim_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$$

Is it possible to solve this limit without Hopital or Taylor (without derivatives)?