It's simple to prove with Hopital that
$$ \lim_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$$
Is it possible to solve this limit without Hopital or Taylor (without derivatives)?
It's simple to prove with Hopital that
$$ \lim_{x \to 0} \frac{x-\sin(x)}{x^3} = \frac{1}{6}$$
Is it possible to solve this limit without Hopital or Taylor (without derivatives)?
I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...
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