How to evaluate n−1∑k=1sin(kθ)sinθ
Any help ? I tried to use difference method. But I'm not getting there.
Answer
HINT:
Use the Prosthaphaeresis Formula,
cos((k−1)θ)−cos((k+1)θ)=2sin(kθ)sin(θ)
and then sum the resulting telescoping series.
How to evaluate n−1∑k=1sin(kθ)sinθ
Any help ? I tried to use difference method. But I'm not getting there.
Answer
HINT:
Use the Prosthaphaeresis Formula,
cos((k−1)θ)−cos((k+1)θ)=2sin(kθ)sin(θ)
and then sum the resulting telescoping series.
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
No comments:
Post a Comment