How to compute: $(89^{3} \bmod 79)^4\bmod 26$??
It's easy to calculate it by evaluating $89^{3}$ first and then mod $79$, but it seems stupid to do it this way. Do we have a faster way to evaluate it?
I have injection $f \colon A \rightarrow B$ and I want to get bijection. Can I just resting codomain to $f(A)$? I know that every function i...
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