Evaluate f(x)=∫π/201(1+x2)(1+tanx)dx
My attempt: I could not apply any standard method known to me to solve this integration. The only way I thought of is expressing tan(x) as an infinite series and expanding into a polynomial. But this will introduce approximation errors.
f(x)=∫π/201(1+x2)(x+x33+2x515+...)dx
or,f(x)=∫π/20(1+x2)−1(x+x33+2x515+...)−1dx
Please let me know how to solve this problem.
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