I have been having trouble finding a suitable counterexample to my problem, which I have written below.
For each n≥1, let fn:R→R be a continuous function and suppose that the sequence of functions (fn)∞n=1 is uniformly bounded. If fn→n→∞f pointwise on R, where f:R→R is continuous, can it be concluded that fn converges to to f uniformly on R?
I think the answer is no, but I can't think of a counterexample. Thanks for any help in advance.
Answer
No, take fn(x)=1/(1+(x−n)2) for example. Then fn→0 pointwise on R, but fn does not converge to 0 uniformly. Why? Because that would say sup But \sup_{\mathbb R} f_n =1 for all n.
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