Monday, July 3, 2017

real analysis - Continuity and uniform convergence counterexample




I have been having trouble finding a suitable counterexample to my problem, which I have written below.



For each n1, let fn:RR be a continuous function and suppose that the sequence of functions (fn)n=1 is uniformly bounded. If fnnf pointwise on R, where f:RR is continuous, can it be concluded that fn converges to to f uniformly on R?



I think the answer is no, but I can't think of a counterexample. Thanks for any help in advance.


Answer



No, take fn(x)=1/(1+(xn)2) for example. Then fn0 pointwise on R, but fn does not converge to 0 uniformly. Why? Because that would say sup But \sup_{\mathbb R} f_n =1 for all n.


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