calculus - Finding the limit of $lim_{k rightarrow infty} left(frac{2^k + 1}{2^{k-1} + 3}right)$

$$\lim_{k \rightarrow \infty} \left(\frac{2^k + 1}{2^{k-1} + 3}\right)$$

I'm trying to prove that the limit of the sequence is $2$ using the squeeze theorem, but with no success.
Thanks

Answer

HINT: Multiply the fraction by $1$ in the carefully chosen disguise

$$\frac{1/2^{k-1}}{1/2^{k-1}}\;.$$