Monday, July 24, 2017

calculus - Limit limxtoinftyxe/ex



I had this problem on my math test, and was stuck on it for quite some time.




limxxe/ex



I knew that the bottom grew faster than the top, but I didn't know how to prove it. I wrote that the limit approaches 0, but I am not sure how to prove it mathematically.


Answer



Show first that it is in indeterminate form.



Then perform L'Hopital's rule, differentiating the top and bottom.



limxxeex=limxexe1ex=e(e1)(e2)limx1x3eex=0


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