I did solve, I got four solutions, but the book says there are only 3.
I considered the cases |x−3|=1 or 3x2−10x+3=0.
I got for x≤0: 2,3,13
I got for x>0: 4
Am I wrong? Is 00=1 or NOT?
Considering the fact that : 22=2⋅2⋅1
21=2⋅1
20=1
00 should be 1 right?
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