Prove:
1×3×5×⋯×(2n−1)2n(n+1)!×4n=1n+1(2nn)
I'm having a bit of trouble proving this, I tried to prove this by induction and would get stuck. Any help is appreciated in advance.
Answer
By multiplying both numerator and denominator by 2⋅4⋅6⋅…⋅(2n)=2nn! we get
1⋅3⋅5⋅…⋅(2n−1)2n(n+1)!=1⋅2⋅3⋅4⋅5⋅6⋅…⋅(2n−1)⋅2n2n(n+1)!⋅2nn!=14n(n+1)⋅(2n)!n!⋅n!=14n(n+1)(2nn)
Then
4n[1⋅3⋅5⋅…⋅(2n−1)2n(n+1)!]=1n+1(2nn)
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