Monday, April 29, 2019

calculus - Convergence of sumin=1nftyfracn!,innn



I need to study this sum: n=1n!innn. Taking: limn|(n!innn)12|


limn|(n!nn)12|



Using Stirling approximation considering the limit:



lnn!nlnnn



then n!(ne)n (is this correct?):



limn|nne|=1e

This doesn't make too much sense because I know the series diverges.



I think I'm missing a 2πn in Stirling approximation but I don't understand why that pops out taking the e() from the first expression.


Answer



The series is absolutely convergent. You don't need Striling's approximation. Just apply ratio test: |an+1||an|1e.


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