I need to study this sum: ∑∞n=1n!innn. Taking: limn→∞|(n!innn)12|
→limn→∞|(n!nn)12|
Using Stirling approximation considering the limit:
lnn!≈nlnn−n
then n!≈(ne)n (is this correct?):
→limn→∞|nne|=1e This doesn't make too much sense because I know the series diverges.
I think I'm missing a √2πn in Stirling approximation but I don't understand why that pops out taking the e() from the first expression.
Answer
The series is absolutely convergent. You don't need Striling's approximation. Just apply ratio test: |an+1||an|→1e.
No comments:
Post a Comment