Wednesday, October 31, 2018

calculus - How to compute the integral of intsin(1x2),dx


I tried substitution, u=1x2,du=2xdx,dx=du2x, yielding:



sinu(du2)=12sin(u)du=12cosu=12cos(1x2)


WolframAlpha is showing something completely different, however. What's wrong with my solution?


Answer



Your substitution is wrong.


Set 1x2=a       dx=121ada


Hence


12sin(a) da1a


Elementary knowledge of analysis tell you that this is a Fresnel Type integral, and the solution can be written as


122πcos(1)(S(22xπ)cot(1)C(22xπ))


Where S and C stand for "Fresnel Sine and Cosine Integral"



Cot stands for the co-tangent.


More on Fresnel Integrals:


https://en.wikipedia.org/wiki/Fresnel_integral


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