I tried substitution, u=1−x2,du=−2xdx,dx=−du2x, yielding:
∫sinu(−du2)=−12∫sin(u)du=−12cosu=−12cos(1−x2)
WolframAlpha is showing something completely different, however. What's wrong with my solution?
Answer
Your substitution is wrong.
Set 1−x2=a dx=−12√1−ada
Hence
−12∫sin(a) da√1−a
Elementary knowledge of analysis tell you that this is a Fresnel Type integral, and the solution can be written as
−12√2πcos(1)(S(√2−2x√π)−cot(1)C(√2−2x√π))
Where S and C stand for "Fresnel Sine and Cosine Integral"
Cot stands for the co-tangent.
More on Fresnel Integrals:
https://en.wikipedia.org/wiki/Fresnel_integral
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