Wednesday, March 15, 2017

elementary set theory - What's the cardinality of all sequences with coefficients in an infinite set?



My motivation for asking this question is that a classmate of mine asked me some kind of question that made me think of this one. I can't recall his exact question because he is kind of messy (both when talking about math and when thinking about math).




I'm kind of stuck though. I feel like the set AN={f:NA,f is a function} should have the same cardinality as the power set of A, if A is infinite. On the other hand, in this post, it is stated that the sequences with real coefficients have the same cardinality as the reals.



It's easy to see that ANP(A), but (obviously) I got stuck on the other inclusion. Is there any general result that says anything else? References would be appreciated.



EDIT To clarify the intetion of this question: I want to know if there are any general results on the cardinality of AN other that it is strictly less than that of the power set of A.



Also, I was aware that the other inclusion isn't true in general (as the post on here I linked to gave a counterexample), but thanks for pointing out why too. :)


Answer



From Jech's Set Theory, we have the following theorems on cardinal exponentiation (a Corollary on page 49):




Theorem. For all α,β, the value of βα is always either:




  • 2β; or

  • α; or

  • cfγγ for some γα where γ is such that cfγβ<γ.



Here, cfγ is the cofinality of γ: the cofinality of a cardinal κ (or of any limit ordinal) is the least limit ordinal δ such that there is an increasing δ-sequence αζζ<δ with lim. The cofinality is always a cardinal, so it makes sense to understand the operations above as cardinal operations.




Corollary. If the Generalized Continuum Hypothesis holds, then
\aleph_{\alpha}^{\aleph_{\beta}} = \left\{\begin{array}{lcl} \aleph_{\alpha} &\quad & \mbox{if $\aleph_{\beta}\lt\mathrm{cf}\;\aleph_{\alpha}$;}\\ \aleph_{\alpha+1} &&\mbox{if $\mathrm{cf}\;\aleph_{\alpha}\leq\aleph_{\beta}\leq\aleph_{\alpha}$;}\\ \aleph_{\beta+1} &&\mbox{if $\aleph_{\alpha}\leq\aleph_{\beta}$.} \end{array}\right.



So, under GCH, for all cardinals \kappa with cofinality greater than \aleph_0 have \kappa^{\aleph_0} = \kappa, and for cardinals \kappa with cofinality \aleph_0 (e.g., \aleph_0, \aleph_{\omega}), we have \kappa^{\aleph_0} = 2^{\kappa}. (In particular, it is not the case the cardinality of A^{\mathbb{N}} is necessarily less than the cardinality of \mathcal{P}(A)).



Then again, GCH is usually considered "boring" by set theorists, from what I understand.



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