Thursday, March 9, 2017

calculus - Test xn=fracn2esqrtncos(1/n) for convergence and give its limit if possible.

Test xn=n2encos(1/n) for convergence and give its limit if possible.



Easy part first: 1/n0 as n and hence cos(1/n)cos(0)=1.



Now the "harder" part. Would you say this arugment is sufficient/correct?







We rewrite the numerator as n21en. Since en grows faster than n2 the term converges towards 0 for n.



So we have limnxn=0/1=0.

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