Test xn=n2e−√ncos(1/n) for convergence and give its limit if possible.
Easy part first: 1/n→0 as n→∞ and hence cos(1/n)→cos(0)=1.
Now the "harder" part. Would you say this arugment is sufficient/correct?
We rewrite the numerator as n21e√n. Since e√n grows faster than n2 the term converges towards 0 for n→∞.
So we have limn→∞xn=0/1=0.
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