I have seen integrals of the form ∫1ax+bdx and ∫1ax2+bx+cdx
But I cannot see how to integrate reciprocals of higher degree - does there exist a general solution to the integrals of reciprocals of cubics, quartics, and higher?
Answer
Reciprocals of higher degree can have their denominators factored into linear and/or irreducible quadratic terms, and from there, our result can be obtained through partial fraction decomposition.
For more details, see Arturo's excellent answer to this question.
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