Find, from first principle, the derivative of: log(ax+b)
My Attempt: f(x)=log(ax+b) f(x+Δx)=log(ax+aΔx+b) Now, f′(x)=lim =\lim_{\Delta x\to 0} \dfrac {\log (ax+a\Delta x+b)-\log(ax+b)}{\Delta x} =\lim_{\Delta x\to 0} \dfrac {\log (\dfrac {ax+a\Delta x+b}{ax+b})}{\Delta x}
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