Proof by contradiction, Assume 21/n is rational so:
21/n=ab
where a,b have no common factors.
2=anbn
2 divides LHS, therefore 2 divides RHS
so 2 divides an or 2 divides bn which implies 2 divides a or 2 divides b.
Stuck on what to do next.
I have injection f:A→B and I want to get bijection. Can I just resting codomain to f(A)? I know that every function i...
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