summation - Prove by induction: $sumlimits_{i=1}^{n}(4i+1) = 2n^2 + 3n$

Prove by induction:
$$\sum\limits_{i=1}^{n}(4i+1) = 2n^2 + 3n$$

It's just the numbers that confuse me; I know how to do a simple induction proof that first for $p(k)$ and then for $k+1$ etc but I don't know how to do it with the form?